Base | Representation |
---|---|
bin | 1011101000110100011111… |
… | …0000000010110011110011 |
3 | 1200022021111001200222111121 |
4 | 2322031013300002303303 |
5 | 3134122011301222124 |
6 | 43114205512323111 |
7 | 2460321416614441 |
oct | 272150760026363 |
9 | 50267431628447 |
10 | 12795911351539 |
11 | 4093796407488 |
12 | 1527b249a3497 |
13 | 71a859579b34 |
14 | 32347ad15b91 |
15 | 172cb72cb2e4 |
hex | ba347c02cf3 |
12795911351539 has 2 divisors, whose sum is σ = 12795911351540. Its totient is φ = 12795911351538.
The previous prime is 12795911351507. The next prime is 12795911351617. The reversal of 12795911351539 is 93515311959721.
12795911351539 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12795911351539 - 25 = 12795911351507 is a prime.
It is not a weakly prime, because it can be changed into another prime (12795911351339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6397955675769 + 6397955675770.
It is an arithmetic number, because the mean of its divisors is an integer number (6397955675770).
Almost surely, 212795911351539 is an apocalyptic number.
12795911351539 is a deficient number, since it is larger than the sum of its proper divisors (1).
12795911351539 is an equidigital number, since it uses as much as digits as its factorization.
12795911351539 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11481750, while the sum is 61.
The spelling of 12795911351539 in words is "twelve trillion, seven hundred ninety-five billion, nine hundred eleven million, three hundred fifty-one thousand, five hundred thirty-nine".
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