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128043150143 = 769166506047
BaseRepresentation
bin111011100111111110…
…1110110101100111111
3110020111112202222021012
41313033331312230333
54044213021301033
6134453333025435
712152012550506
oct1671775665477
9406445688235
10128043150143
114a337024947
122099548527b
13c0c7657acc
1462a964383d
1534e6176248
hex1dcff76b3f

128043150143 has 4 divisors (see below), whose sum is σ = 128209656960. Its totient is φ = 127876643328.

The previous prime is 128043150127. The next prime is 128043150223. The reversal of 128043150143 is 341051340821.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 341051340821 = 1237927550799.

It is a cyclic number.

It is not a de Polignac number, because 128043150143 - 24 = 128043150127 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (128043155143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83252255 + ... + 83253792.

It is an arithmetic number, because the mean of its divisors is an integer number (32052414240).

Almost surely, 2128043150143 is an apocalyptic number.

128043150143 is a deficient number, since it is larger than the sum of its proper divisors (166506817).

128043150143 is an equidigital number, since it uses as much as digits as its factorization.

128043150143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 166506816.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 128043150143 its reverse (341051340821), we get a palindrome (469094490964).

The spelling of 128043150143 in words is "one hundred twenty-eight billion, forty-three million, one hundred fifty thousand, one hundred forty-three".

Divisors: 1 769 166506047 128043150143