Base | Representation |
---|---|
bin | 10010101001001000100… |
… | …011110100111100000111 |
3 | 11112110210021210102200212 |
4 | 102221020203310330013 |
5 | 131442212101340024 |
6 | 2420312020230035 |
7 | 161362200655064 |
oct | 22511043647407 |
9 | 4473707712625 |
10 | 1281117605639 |
11 | 4543565428a3 |
12 | 18835783b31b |
13 | 93a69125b21 |
14 | 460138a5c6b |
15 | 234d136ba0e |
hex | 12a488f4f07 |
1281117605639 has 2 divisors, whose sum is σ = 1281117605640. Its totient is φ = 1281117605638.
The previous prime is 1281117605591. The next prime is 1281117605653. The reversal of 1281117605639 is 9365067111821.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1281117605639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1281117605039) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 640558802819 + 640558802820.
It is an arithmetic number, because the mean of its divisors is an integer number (640558802820).
Almost surely, 21281117605639 is an apocalyptic number.
1281117605639 is a deficient number, since it is larger than the sum of its proper divisors (1).
1281117605639 is an equidigital number, since it uses as much as digits as its factorization.
1281117605639 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 544320, while the sum is 50.
The spelling of 1281117605639 in words is "one trillion, two hundred eighty-one billion, one hundred seventeen million, six hundred five thousand, six hundred thirty-nine".
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