Base | Representation |
---|---|
bin | 1011101001110000100101… |
… | …0011000000000110010000 |
3 | 1200100211010100000222020110 |
4 | 2322130021103000012100 |
5 | 3134403031103420143 |
6 | 43125434350441320 |
7 | 2461432244132235 |
oct | 272341123000620 |
9 | 50324110028213 |
10 | 12812043420048 |
11 | 409a614557304 |
12 | 152b087503240 |
13 | 71c22a7c41c2 |
14 | 32416b62578c |
15 | 17340d6ad533 |
hex | ba7094c0190 |
12812043420048 has 80 divisors (see below), whose sum is σ = 35045799443136. Its totient is φ = 4019339304960.
The previous prime is 12812043419887. The next prime is 12812043420049. The reversal of 12812043420048 is 84002434021821.
It is a junction number, because it is equal to n+sod(n) for n = 12812043419988 and 12812043420015.
It is not an unprimeable number, because it can be changed into a prime (12812043420049) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27935143 + ... + 28390073.
Almost surely, 212812043420048 is an apocalyptic number.
It is an amenable number.
12812043420048 is an abundant number, since it is smaller than the sum of its proper divisors (22233756023088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12812043420048 is a wasteful number, since it uses less digits than its factorization.
12812043420048 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 489472 (or 489466 counting only the distinct ones).
The product of its (nonzero) digits is 98304, while the sum is 39.
Adding to 12812043420048 its reverse (84002434021821), we get a palindrome (96814477441869).
The spelling of 12812043420048 in words is "twelve trillion, eight hundred twelve billion, forty-three million, four hundred twenty thousand, forty-eight".
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