Base | Representation |
---|---|
bin | 1011101001110101001111… |
… | …1000011100010001101101 |
3 | 1200100221100112122001120002 |
4 | 2322131103320130101231 |
5 | 3134413111423430111 |
6 | 43130202451034045 |
7 | 2461505250221042 |
oct | 272352370342155 |
9 | 50327315561502 |
10 | 12813294748781 |
11 | 40a00a693108a |
12 | 152b37659b925 |
13 | 71c399b1a7c7 |
14 | 3242498b71c9 |
15 | 17348348763b |
hex | ba753e1c46d |
12813294748781 has 2 divisors, whose sum is σ = 12813294748782. Its totient is φ = 12813294748780.
The previous prime is 12813294748729. The next prime is 12813294748883. The reversal of 12813294748781 is 18784749231821.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9544824880900 + 3268469867881 = 3089470^2 + 1807891^2 .
It is a cyclic number.
It is not a de Polignac number, because 12813294748781 - 238 = 12538416841837 is a prime.
It is a super-2 number, since 2×128132947487812 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12813294744781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6406647374390 + 6406647374391.
It is an arithmetic number, because the mean of its divisors is an integer number (6406647374391).
Almost surely, 212813294748781 is an apocalyptic number.
It is an amenable number.
12813294748781 is a deficient number, since it is larger than the sum of its proper divisors (1).
12813294748781 is an equidigital number, since it uses as much as digits as its factorization.
12813294748781 is an evil number, because the sum of its binary digits is even.
The product of its digits is 43352064, while the sum is 65.
The spelling of 12813294748781 in words is "twelve trillion, eight hundred thirteen billion, two hundred ninety-four million, seven hundred forty-eight thousand, seven hundred eighty-one".
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