Base | Representation |
---|---|
bin | 10111110111101001… |
… | …10100110110100101 |
3 | 1020002002102112022111 |
4 | 23323310310312211 |
5 | 202221101120111 |
6 | 5515335001021 |
7 | 632364354616 |
oct | 137364646645 |
9 | 36062375274 |
10 | 12814863781 |
11 | 5486724915 |
12 | 2597809171 |
13 | 1292c20045 |
14 | 897d35c0d |
15 | 500081a21 |
hex | 2fbd34da5 |
12814863781 has 2 divisors, whose sum is σ = 12814863782. Its totient is φ = 12814863780.
The previous prime is 12814863757. The next prime is 12814863791. The reversal of 12814863781 is 18736841821.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11285662756 + 1529201025 = 106234^2 + 39105^2 .
It is a cyclic number.
It is not a de Polignac number, because 12814863781 - 219 = 12814339493 is a prime.
It is a super-2 number, since 2×128148637812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12814863791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6407431890 + 6407431891.
It is an arithmetic number, because the mean of its divisors is an integer number (6407431891).
Almost surely, 212814863781 is an apocalyptic number.
It is an amenable number.
12814863781 is a deficient number, since it is larger than the sum of its proper divisors (1).
12814863781 is an equidigital number, since it uses as much as digits as its factorization.
12814863781 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 516096, while the sum is 49.
The spelling of 12814863781 in words is "twelve billion, eight hundred fourteen million, eight hundred sixty-three thousand, seven hundred eighty-one".
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