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128250262726847 is a prime number
BaseRepresentation
bin11101001010010010010111…
…010110100010100010111111
3121211002121100022122012101222
4131022102113112202202333
5113302223014224224342
61132433205103423555
736004530032242562
oct3512222726424277
9554077308565358
10128250262726847
11379566a3917218
12124739155b4bbb
135673c4265a191
1423954bad904d9
15ec613c4ceed2
hex74a4975a28bf

128250262726847 has 2 divisors, whose sum is σ = 128250262726848. Its totient is φ = 128250262726846.

The previous prime is 128250262726727. The next prime is 128250262726853. The reversal of 128250262726847 is 748627262052821.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 128250262726847 - 238 = 127975384819903 is a prime.

It is a super-3 number, since 3×1282502627268473 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 128250262726847.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (128250262726897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64125131363423 + 64125131363424.

It is an arithmetic number, because the mean of its divisors is an integer number (64125131363424).

Almost surely, 2128250262726847 is an apocalyptic number.

128250262726847 is a deficient number, since it is larger than the sum of its proper divisors (1).

128250262726847 is an equidigital number, since it uses as much as digits as its factorization.

128250262726847 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72253440, while the sum is 62.

The spelling of 128250262726847 in words is "one hundred twenty-eight trillion, two hundred fifty billion, two hundred sixty-two million, seven hundred twenty-six thousand, eight hundred forty-seven".