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12830088127 is a prime number
BaseRepresentation
bin10111111001011101…
…11001101110111111
31020010011002000012011
423330232321232333
5202234000310002
65521041152051
7632640643513
oct137456715677
936104060164
1012830088127
11549428311a
1225a092b627
13129612082c
14899d7a143
1550158c8d7
hex2fcbb9bbf

12830088127 has 2 divisors, whose sum is σ = 12830088128. Its totient is φ = 12830088126.

The previous prime is 12830088119. The next prime is 12830088133. The reversal of 12830088127 is 72188003821.

It is a strong prime.

It is an emirp because it is prime and its reverse (72188003821) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12830088127 - 23 = 12830088119 is a prime.

It is a super-4 number, since 4×128300881274 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 12830088127.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12830088197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6415044063 + 6415044064.

It is an arithmetic number, because the mean of its divisors is an integer number (6415044064).

Almost surely, 212830088127 is an apocalyptic number.

12830088127 is a deficient number, since it is larger than the sum of its proper divisors (1).

12830088127 is an equidigital number, since it uses as much as digits as its factorization.

12830088127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43008, while the sum is 40.

The spelling of 12830088127 in words is "twelve billion, eight hundred thirty million, eighty-eight thousand, one hundred twenty-seven".