Base | Representation |
---|---|
bin | 10111111001011101… |
… | …11001101110111111 |
3 | 1020010011002000012011 |
4 | 23330232321232333 |
5 | 202234000310002 |
6 | 5521041152051 |
7 | 632640643513 |
oct | 137456715677 |
9 | 36104060164 |
10 | 12830088127 |
11 | 549428311a |
12 | 25a092b627 |
13 | 129612082c |
14 | 899d7a143 |
15 | 50158c8d7 |
hex | 2fcbb9bbf |
12830088127 has 2 divisors, whose sum is σ = 12830088128. Its totient is φ = 12830088126.
The previous prime is 12830088119. The next prime is 12830088133. The reversal of 12830088127 is 72188003821.
It is a strong prime.
It is an emirp because it is prime and its reverse (72188003821) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12830088127 - 23 = 12830088119 is a prime.
It is a super-4 number, since 4×128300881274 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 12830088127.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12830088197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6415044063 + 6415044064.
It is an arithmetic number, because the mean of its divisors is an integer number (6415044064).
Almost surely, 212830088127 is an apocalyptic number.
12830088127 is a deficient number, since it is larger than the sum of its proper divisors (1).
12830088127 is an equidigital number, since it uses as much as digits as its factorization.
12830088127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43008, while the sum is 40.
The spelling of 12830088127 in words is "twelve billion, eight hundred thirty million, eighty-eight thousand, one hundred twenty-seven".
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