Base | Representation |
---|---|
bin | 11101001011110110010011… |
… | …011000010000010011111111 |
3 | 121211110212022202200011212201 |
4 | 131023312103120100103333 |
5 | 113311002300440444413 |
6 | 1132554353112212331 |
7 | 36015346151162344 |
oct | 3513662330202377 |
9 | 554425282604781 |
10 | 128357570249983 |
11 | 3799815a149638 |
12 | 1249068269a0a7 |
13 | 56810b40a59b9 |
14 | 239a77a73c7cb |
15 | ec8d1d02b9dd |
hex | 74bd936104ff |
128357570249983 has 2 divisors, whose sum is σ = 128357570249984. Its totient is φ = 128357570249982.
The previous prime is 128357570249977. The next prime is 128357570250011. The reversal of 128357570249983 is 389942075753821.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-128357570249983 is a prime.
It is a super-2 number, since 2×1283575702499832 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (128357570249963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64178785124991 + 64178785124992.
It is an arithmetic number, because the mean of its divisors is an integer number (64178785124992).
Almost surely, 2128357570249983 is an apocalyptic number.
128357570249983 is a deficient number, since it is larger than the sum of its proper divisors (1).
128357570249983 is an equidigital number, since it uses as much as digits as its factorization.
128357570249983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 914457600, while the sum is 73.
The spelling of 128357570249983 in words is "one hundred twenty-eight trillion, three hundred fifty-seven billion, five hundred seventy million, two hundred forty-nine thousand, nine hundred eighty-three".
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