128387254001 has 2 divisors, whose sum is σ = 128387254002. Its totient is φ = 128387254000.

The previous prime is 128387253997. The next prime is 128387254003. The reversal of 128387254001 is 100452783821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72320117776 + 56067136225 = 268924^2 + 236785^2 .

It is a cyclic number.

It is not a de Polignac number, because 128387254001 - 2² = 128387253997 is a prime.

Together with 128387254003, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 128387254001.

It is not a weakly prime, because it can be changed into another prime (128387254003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64193627000 + 64193627001.

It is an arithmetic number, because the mean of its divisors is an integer number (64193627001).

Almost surely, 2^128387254001 is an apocalyptic number.

It is an amenable number.

128387254001 is a deficient number, since it is larger than the sum of its proper divisors (1).

128387254001 is an equidigital number, since it uses as much as digits as its factorization.

128387254001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 107520, while the sum is 41.

The spelling of 128387254001 in words is "one hundred twenty-eight billion, three hundred eighty-seven million, two hundred fifty-four thousand, one".