Base | Representation |
---|---|
bin | 10010101011110110001… |
… | …110010101001100110001 |
3 | 11112202022100020200021111 |
4 | 102223312032111030301 |
5 | 132014143442044233 |
6 | 2421513100553321 |
7 | 161524330112251 |
oct | 22536616251461 |
9 | 4482270220244 |
10 | 1284031206193 |
11 | 45561116103a |
12 | 188a2b552841 |
13 | 94111949218 |
14 | 4620c81b961 |
15 | 23602045acd |
hex | 12af6395331 |
1284031206193 has 2 divisors, whose sum is σ = 1284031206194. Its totient is φ = 1284031206192.
The previous prime is 1284031206187. The next prime is 1284031206281. The reversal of 1284031206193 is 3916021304821.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 774018127089 + 510013079104 = 879783^2 + 714152^2 .
It is a cyclic number.
It is not a de Polignac number, because 1284031206193 - 229 = 1283494335281 is a prime.
It is a super-2 number, since 2×12840312061932 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1284031206103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 642015603096 + 642015603097.
It is an arithmetic number, because the mean of its divisors is an integer number (642015603097).
Almost surely, 21284031206193 is an apocalyptic number.
It is an amenable number.
1284031206193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1284031206193 is an equidigital number, since it uses as much as digits as its factorization.
1284031206193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 40.
The spelling of 1284031206193 in words is "one trillion, two hundred eighty-four billion, thirty-one million, two hundred six thousand, one hundred ninety-three".
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