12840953 has 2 divisors, whose sum is σ = 12840954. Its totient is φ = 12840952.

The previous prime is 12840943. The next prime is 12841007. The reversal of 12840953 is 35904821.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7327849 + 5513104 = 2707^2 + 2348^2 .

It is an emirp because it is prime and its reverse (35904821) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12840953 - 2⁸ = 12840697 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12840943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6420476 + 6420477.

It is an arithmetic number, because the mean of its divisors is an integer number (6420477).

Almost surely, 2^12840953 is an apocalyptic number.

It is an amenable number.

12840953 is a deficient number, since it is larger than the sum of its proper divisors (1).

12840953 is an equidigital number, since it uses as much as digits as its factorization.

12840953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 32.

The square root of 12840953 is about 3583.4275491490. The cubic root of 12840953 is about 234.1706270077.

The spelling of 12840953 in words is "twelve million, eight hundred forty thousand, nine hundred fifty-three".