Base | Representation |
---|---|
bin | 1011101100000101100001… |
… | …0010000000000101010011 |
3 | 1200111122022121011110020202 |
4 | 2323001120102000011103 |
5 | 3141031420423413241 |
6 | 43200045445325415 |
7 | 2464346055162632 |
oct | 273013022000523 |
9 | 50448277143222 |
10 | 12852023263571 |
11 | 41055700984a8 |
12 | 153698470686b |
13 | 722c2c63a04b |
14 | 326081267519 |
15 | 17449d512d9b |
hex | bb058480153 |
12852023263571 has 2 divisors, whose sum is σ = 12852023263572. Its totient is φ = 12852023263570.
The previous prime is 12852023263523. The next prime is 12852023263603. The reversal of 12852023263571 is 17536232025821.
It is a strong prime.
It is an emirp because it is prime and its reverse (17536232025821) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12852023263571 - 214 = 12852023247187 is a prime.
It is not a weakly prime, because it can be changed into another prime (12852023263511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6426011631785 + 6426011631786.
It is an arithmetic number, because the mean of its divisors is an integer number (6426011631786).
Almost surely, 212852023263571 is an apocalyptic number.
12852023263571 is a deficient number, since it is larger than the sum of its proper divisors (1).
12852023263571 is an equidigital number, since it uses as much as digits as its factorization.
12852023263571 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1209600, while the sum is 47.
The spelling of 12852023263571 in words is "twelve trillion, eight hundred fifty-two billion, twenty-three million, two hundred sixty-three thousand, five hundred seventy-one".
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