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128568385117 is a prime number
BaseRepresentation
bin111011110111101000…
…1011101111001011101
3110021212011002200012101
41313233101131321131
54101302001310432
6135021414405101
712201021146014
oct1675721357135
9407764080171
10128568385117
114a586557737
1220b01360791
13c17c407033
1463192c7a7b
1535273264e7
hex1def45de5d

128568385117 has 2 divisors, whose sum is σ = 128568385118. Its totient is φ = 128568385116.

The previous prime is 128568385087. The next prime is 128568385171. The reversal of 128568385117 is 711583865821.

Together with next prime (128568385171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92214861561 + 36353523556 = 303669^2 + 190666^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-128568385117 is a prime.

It is a super-3 number, since 3×1285683851173 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (128568380117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64284192558 + 64284192559.

It is an arithmetic number, because the mean of its divisors is an integer number (64284192559).

Almost surely, 2128568385117 is an apocalyptic number.

It is an amenable number.

128568385117 is a deficient number, since it is larger than the sum of its proper divisors (1).

128568385117 is an equidigital number, since it uses as much as digits as its factorization.

128568385117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3225600, while the sum is 55.

The spelling of 128568385117 in words is "one hundred twenty-eight billion, five hundred sixty-eight million, three hundred eighty-five thousand, one hundred seventeen".