Base | Representation |
---|---|
bin | 1011101101101000000001… |
… | …1010111001011000111111 |
3 | 1200121011120110202102121112 |
4 | 2323122000122321120333 |
5 | 3142000044410102441 |
6 | 43220141423352235 |
7 | 2466303255654215 |
oct | 273320032713077 |
9 | 50534513672545 |
10 | 12878466487871 |
11 | 41157aa656286 |
12 | 153bb2445267b |
13 | 725584b7732a |
14 | 32746d174cb5 |
15 | 174ee9c674eb |
hex | bb6806b963f |
12878466487871 has 2 divisors, whose sum is σ = 12878466487872. Its totient is φ = 12878466487870.
The previous prime is 12878466487837. The next prime is 12878466487879. The reversal of 12878466487871 is 17878466487821.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12878466487871 is a prime.
It is a super-2 number, since 2×128784664878712 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12878466487792 and 12878466487801.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12878466487879) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6439233243935 + 6439233243936.
It is an arithmetic number, because the mean of its divisors is an integer number (6439233243936).
Almost surely, 212878466487871 is an apocalyptic number.
12878466487871 is a deficient number, since it is larger than the sum of its proper divisors (1).
12878466487871 is an equidigital number, since it uses as much as digits as its factorization.
12878466487871 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1618477056, while the sum is 77.
The spelling of 12878466487871 in words is "twelve trillion, eight hundred seventy-eight billion, four hundred sixty-six million, four hundred eighty-seven thousand, eight hundred seventy-one".
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