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1288320635947 is a prime number
BaseRepresentation
bin10010101111110101111…
…001001101010000101011
311120011101021120021201011
4102233311321031100223
5132101440040322242
62423502450204351
7162035533502332
oct22576571152053
94504337507634
101288320635947
1145741245a104
12189827b836b7
1394646507437
14464d8392d19
15237a38dcd17
hex12bf5e4d42b

1288320635947 has 2 divisors, whose sum is σ = 1288320635948. Its totient is φ = 1288320635946.

The previous prime is 1288320635827. The next prime is 1288320635951. The reversal of 1288320635947 is 7495360238821.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1288320635947 - 215 = 1288320603179 is a prime.

It is a super-2 number, since 2×12883206359472 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1288320635891 and 1288320635900.

It is not a weakly prime, because it can be changed into another prime (1288320635747) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 644160317973 + 644160317974.

It is an arithmetic number, because the mean of its divisors is an integer number (644160317974).

It is a 1-persistent number, because it is pandigital, but 2⋅1288320635947 = 2576641271894 is not.

Almost surely, 21288320635947 is an apocalyptic number.

1288320635947 is a deficient number, since it is larger than the sum of its proper divisors (1).

1288320635947 is an equidigital number, since it uses as much as digits as its factorization.

1288320635947 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17418240, while the sum is 58.

The spelling of 1288320635947 in words is "one trillion, two hundred eighty-eight billion, three hundred twenty million, six hundred thirty-five thousand, nine hundred forty-seven".