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1289021703881 is a prime number
BaseRepresentation
bin10010110000011111101…
…011100100011011001001
311120020012010202020010012
4102300133223210123021
5132104404024011011
62424100212401305
7162062105462222
oct22603753443311
94506163666105
101289021703881
1145774216889a
121899a2916235
139472882b932
1446563528249
15237e5221a8b
hex12c1fae46c9

1289021703881 has 2 divisors, whose sum is σ = 1289021703882. Its totient is φ = 1289021703880.

The previous prime is 1289021703863. The next prime is 1289021703883. The reversal of 1289021703881 is 1883071209821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1106956494400 + 182065209481 = 1052120^2 + 426691^2 .

It is an emirp because it is prime and its reverse (1883071209821) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1289021703881 - 26 = 1289021703817 is a prime.

It is a super-2 number, since 2×12890217038812 (a number of 25 digits) contains 22 as substring.

Together with 1289021703883, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1289021703883) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 644510851940 + 644510851941.

It is an arithmetic number, because the mean of its divisors is an integer number (644510851941).

Almost surely, 21289021703881 is an apocalyptic number.

It is an amenable number.

1289021703881 is a deficient number, since it is larger than the sum of its proper divisors (1).

1289021703881 is an equidigital number, since it uses as much as digits as its factorization.

1289021703881 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 387072, while the sum is 50.

The spelling of 1289021703881 in words is "one trillion, two hundred eighty-nine billion, twenty-one million, seven hundred three thousand, eight hundred eighty-one".