Base | Representation |
---|---|
bin | 111100000100110010… |
… | …0001011100000000001 |
3 | 110022222220010112110202 |
4 | 1320021210023200001 |
5 | 4103202412414423 |
6 | 135133253134545 |
7 | 12214655432516 |
oct | 1701144134001 |
9 | 408886115422 |
10 | 129009498113 |
11 | 4a792553431 |
12 | 2100502a455 |
13 | c21c911942 |
14 | 635bb1130d |
15 | 3550e0b728 |
hex | 1e0990b801 |
129009498113 has 2 divisors, whose sum is σ = 129009498114. Its totient is φ = 129009498112.
The previous prime is 129009498083. The next prime is 129009498151. The reversal of 129009498113 is 311894900921.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 128915466304 + 94031809 = 359048^2 + 9697^2 .
It is a cyclic number.
It is not a de Polignac number, because 129009498113 - 222 = 129005303809 is a prime.
It is not a weakly prime, because it can be changed into another prime (129009498173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64504749056 + 64504749057.
It is an arithmetic number, because the mean of its divisors is an integer number (64504749057).
Almost surely, 2129009498113 is an apocalyptic number.
It is an amenable number.
129009498113 is a deficient number, since it is larger than the sum of its proper divisors (1).
129009498113 is an equidigital number, since it uses as much as digits as its factorization.
129009498113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139968, while the sum is 47.
The spelling of 129009498113 in words is "one hundred twenty-nine billion, nine million, four hundred ninety-eight thousand, one hundred thirteen".
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