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1291243012907 is a prime number
BaseRepresentation
bin10010110010100100000…
…101001100001100101011
311120102220221112102020212
4102302210011030030223
5132123431202403112
62425104443011335
7162201130341641
oct22624405141453
94512827472225
101291243012907
11458682022181
1218a302809b4b
13949c0ab1483
14466d4551191
15238c524c522
hex12ca414c32b

1291243012907 has 2 divisors, whose sum is σ = 1291243012908. Its totient is φ = 1291243012906.

The previous prime is 1291243012817. The next prime is 1291243012909. The reversal of 1291243012907 is 7092103421921.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1291243012907 - 214 = 1291242996523 is a prime.

It is a super-2 number, since 2×12912430129072 (a number of 25 digits) contains 22 as substring.

Together with 1291243012909, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1291243012909) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 645621506453 + 645621506454.

It is an arithmetic number, because the mean of its divisors is an integer number (645621506454).

Almost surely, 21291243012907 is an apocalyptic number.

1291243012907 is a deficient number, since it is larger than the sum of its proper divisors (1).

1291243012907 is an equidigital number, since it uses as much as digits as its factorization.

1291243012907 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432, while the sum is 41.

The spelling of 1291243012907 in words is "one trillion, two hundred ninety-one billion, two hundred forty-three million, twelve thousand, nine hundred seven".