Base | Representation |
---|---|
bin | 1011101111101011110000… |
… | …1011011000101100001111 |
3 | 1200201112211221011122220010 |
4 | 2323322330023120230033 |
5 | 3143040010132334403 |
6 | 43244310412324303 |
7 | 2501664500415060 |
oct | 273727413305417 |
9 | 50645757148803 |
10 | 12913828793103 |
11 | 41297a6766627 |
12 | 1546953173693 |
13 | 7289cc1720b4 |
14 | 329065832567 |
15 | 175db9512603 |
hex | bbebc2d8b0f |
12913828793103 has 32 divisors (see below), whose sum is σ = 20927456381440. Its totient is φ = 6918873292800.
The previous prime is 12913828793087. The next prime is 12913828793111. The reversal of 12913828793103 is 30139782831921.
It is not a de Polignac number, because 12913828793103 - 24 = 12913828793087 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (57).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12913828793113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 166793698 + ... + 166871103.
It is an arithmetic number, because the mean of its divisors is an integer number (653983011920).
Almost surely, 212913828793103 is an apocalyptic number.
12913828793103 is a deficient number, since it is larger than the sum of its proper divisors (8013627588337).
12913828793103 is a wasteful number, since it uses less digits than its factorization.
12913828793103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 333664927.
The product of its (nonzero) digits is 3919104, while the sum is 57.
The spelling of 12913828793103 in words is "twelve trillion, nine hundred thirteen billion, eight hundred twenty-eight million, seven hundred ninety-three thousand, one hundred three".
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