Base | Representation |
---|---|
bin | 11000000110001100… |
… | …11001101110011101 |
3 | 1020101121002012200111 |
4 | 30003012121232131 |
5 | 202443322134043 |
6 | 5535414530021 |
7 | 635405635642 |
oct | 140306315635 |
9 | 36347065614 |
10 | 12936911773 |
11 | 5539605325 |
12 | 2610666911 |
13 | 12b22b31a6 |
14 | 8aa225dc9 |
15 | 50ab3e09d |
hex | 303199b9d |
12936911773 has 2 divisors, whose sum is σ = 12936911774. Its totient is φ = 12936911772.
The previous prime is 12936911747. The next prime is 12936911789. The reversal of 12936911773 is 37711963921.
12936911773 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11635289689 + 1301622084 = 107867^2 + 36078^2 .
It is a cyclic number.
It is not a de Polignac number, because 12936911773 - 221 = 12934814621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12936911873) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6468455886 + 6468455887.
It is an arithmetic number, because the mean of its divisors is an integer number (6468455887).
Almost surely, 212936911773 is an apocalyptic number.
It is an amenable number.
12936911773 is a deficient number, since it is larger than the sum of its proper divisors (1).
12936911773 is an equidigital number, since it uses as much as digits as its factorization.
12936911773 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 428652, while the sum is 49.
The spelling of 12936911773 in words is "twelve billion, nine hundred thirty-six million, nine hundred eleven thousand, seven hundred seventy-three".
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