Base | Representation |
---|---|
bin | 1011110001000110110100… |
… | …1101111001010100111111 |
3 | 1200210212221112212110102221 |
4 | 2330101231031321110333 |
5 | 3143440041101323113 |
6 | 43303432211030211 |
7 | 2503521326126344 |
oct | 274215515712477 |
9 | 50725845773387 |
10 | 12938273854783 |
11 | 4139100322242 |
12 | 154b63589b367 |
13 | 72b0c6729434 |
14 | 32a3042027cb |
15 | 17684a61898d |
hex | bc46d37953f |
12938273854783 has 2 divisors, whose sum is σ = 12938273854784. Its totient is φ = 12938273854782.
The previous prime is 12938273854703. The next prime is 12938273854813. The reversal of 12938273854783 is 38745837283921.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12938273854783 is a prime.
It is a super-2 number, since 2×129382738547832 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12938273854703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6469136927391 + 6469136927392.
It is an arithmetic number, because the mean of its divisors is an integer number (6469136927392).
Almost surely, 212938273854783 is an apocalyptic number.
12938273854783 is a deficient number, since it is larger than the sum of its proper divisors (1).
12938273854783 is an equidigital number, since it uses as much as digits as its factorization.
12938273854783 is an evil number, because the sum of its binary digits is even.
The product of its digits is 487710720, while the sum is 70.
The spelling of 12938273854783 in words is "twelve trillion, nine hundred thirty-eight billion, two hundred seventy-three million, eight hundred fifty-four thousand, seven hundred eighty-three".
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