Base | Representation |
---|---|
bin | 1011110001001000100001… |
… | …0100110101111010101011 |
3 | 1200210221010020122222210201 |
4 | 2330102020110311322223 |
5 | 3143442004014120101 |
6 | 43303545255053031 |
7 | 2503535520663103 |
oct | 274221024657253 |
9 | 50727106588721 |
10 | 12938728660651 |
11 | 4139314020662 |
12 | 154b742071177 |
13 | 72b169a19731 |
14 | 32a348792203 |
15 | 176875505e01 |
hex | bc488535eab |
12938728660651 has 2 divisors, whose sum is σ = 12938728660652. Its totient is φ = 12938728660650.
The previous prime is 12938728660423. The next prime is 12938728660679. The reversal of 12938728660651 is 15606682783921.
12938728660651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12938728660651 - 223 = 12938720272043 is a prime.
It is not a weakly prime, because it can be changed into another prime (12938728660751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6469364330325 + 6469364330326.
It is an arithmetic number, because the mean of its divisors is an integer number (6469364330326).
Almost surely, 212938728660651 is an apocalyptic number.
12938728660651 is a deficient number, since it is larger than the sum of its proper divisors (1).
12938728660651 is an equidigital number, since it uses as much as digits as its factorization.
12938728660651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52254720, while the sum is 64.
The spelling of 12938728660651 in words is "twelve trillion, nine hundred thirty-eight billion, seven hundred twenty-eight million, six hundred sixty thousand, six hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •