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129424718281 is a prime number
BaseRepresentation
bin111100010001001010…
…0000111100111001001
3110101001211102220110111
41320202110013213021
54110030211441111
6135242404514321
712231156645115
oct1704224074711
9411054386414
10129424718281
114a9859744a1
12211000ab9a1
13c287951b51
14639ad18745
1535775c9a21
hex1e225079c9

129424718281 has 2 divisors, whose sum is σ = 129424718282. Its totient is φ = 129424718280.

The previous prime is 129424718239. The next prime is 129424718323. The reversal of 129424718281 is 182817424921.

It is a balanced prime because it is at equal distance from previous prime (129424718239) and next prime (129424718323).

It can be written as a sum of positive squares in only one way, i.e., 83995632400 + 45429085881 = 289820^2 + 213141^2 .

It is a cyclic number.

It is not a de Polignac number, because 129424718281 - 213 = 129424710089 is a prime.

It is a super-2 number, since 2×1294247182812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (129424718201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64712359140 + 64712359141.

It is an arithmetic number, because the mean of its divisors is an integer number (64712359141).

Almost surely, 2129424718281 is an apocalyptic number.

It is an amenable number.

129424718281 is a deficient number, since it is larger than the sum of its proper divisors (1).

129424718281 is an equidigital number, since it uses as much as digits as its factorization.

129424718281 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 516096, while the sum is 49.

The spelling of 129424718281 in words is "one hundred twenty-nine billion, four hundred twenty-four million, seven hundred eighteen thousand, two hundred eighty-one".