Base | Representation |
---|---|
bin | 1011110001011010110100… |
… | …0010000010110111100001 |
3 | 1200211101210111012022022012 |
4 | 2330112231002002313201 |
5 | 3144032033200112444 |
6 | 43310120442322305 |
7 | 2504101311033254 |
oct | 274265502026741 |
9 | 50741714168265 |
10 | 12943639457249 |
11 | 4140404040846 |
12 | 15506927b9395 |
13 | 72b770244b37 |
14 | 32a692a7309b |
15 | 176a616dbb9e |
hex | bc5ad082de1 |
12943639457249 has 2 divisors, whose sum is σ = 12943639457250. Its totient is φ = 12943639457248.
The previous prime is 12943639457213. The next prime is 12943639457251. The reversal of 12943639457249 is 94275493634921.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11579490208225 + 1364149249024 = 3402865^2 + 1167968^2 .
It is a cyclic number.
It is not a de Polignac number, because 12943639457249 - 216 = 12943639391713 is a prime.
Together with 12943639457251, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12943639457149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6471819728624 + 6471819728625.
It is an arithmetic number, because the mean of its divisors is an integer number (6471819728625).
Almost surely, 212943639457249 is an apocalyptic number.
It is an amenable number.
12943639457249 is a deficient number, since it is larger than the sum of its proper divisors (1).
12943639457249 is an equidigital number, since it uses as much as digits as its factorization.
12943639457249 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 352719360, while the sum is 68.
The spelling of 12943639457249 in words is "twelve trillion, nine hundred forty-three billion, six hundred thirty-nine million, four hundred fifty-seven thousand, two hundred forty-nine".
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