Base | Representation |
---|---|
bin | 111100010011011001… |
… | …1101111101110001010 |
3 | 110101021002022121021220 |
4 | 1320212303233232022 |
5 | 4110204012233043 |
6 | 135254100542510 |
7 | 12233063561064 |
oct | 1704663575612 |
9 | 411232277256 |
10 | 129500117898 |
11 | 4aa14493328 |
12 | 211213b1a36 |
13 | c29a4612c8 |
14 | 63a6d44734 |
15 | 357e020483 |
hex | 1e26cefb8a |
129500117898 has 64 divisors (see below), whose sum is σ = 283174797312. Its totient is φ = 39304016640.
The previous prime is 129500117869. The next prime is 129500117899. The reversal of 129500117898 is 898711005921.
129500117898 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a self number, because there is not a number n which added to its sum of digits gives 129500117898.
It is not an unprimeable number, because it can be changed into a prime (129500117899) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14740015 + ... + 14748797.
It is an arithmetic number, because the mean of its divisors is an integer number (4424606208).
Almost surely, 2129500117898 is an apocalyptic number.
129500117898 is an abundant number, since it is smaller than the sum of its proper divisors (153674679414).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
129500117898 is a wasteful number, since it uses less digits than its factorization.
129500117898 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13499.
The product of its (nonzero) digits is 362880, while the sum is 51.
The spelling of 129500117898 in words is "one hundred twenty-nine billion, five hundred million, one hundred seventeen thousand, eight hundred ninety-eight".
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