Base | Representation |
---|---|
bin | 11000001000000000… |
… | …10010000111111111 |
3 | 1020102122122002102112 |
4 | 30010000102013333 |
5 | 203011213204431 |
6 | 5541120044235 |
7 | 635651622506 |
oct | 140400220777 |
9 | 36378562375 |
10 | 12952084991 |
11 | 554712917a |
12 | 261576367b |
13 | 12b5496621 |
14 | 8ac25583d |
15 | 50c139c2b |
hex | 3040121ff |
12952084991 has 2 divisors, whose sum is σ = 12952084992. Its totient is φ = 12952084990.
The previous prime is 12952084927. The next prime is 12952085017. The reversal of 12952084991 is 19948025921.
It is a strong prime.
It is an emirp because it is prime and its reverse (19948025921) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12952084991 - 26 = 12952084927 is a prime.
It is a super-2 number, since 2×129520849912 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12952084391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6476042495 + 6476042496.
It is an arithmetic number, because the mean of its divisors is an integer number (6476042496).
Almost surely, 212952084991 is an apocalyptic number.
12952084991 is a deficient number, since it is larger than the sum of its proper divisors (1).
12952084991 is an equidigital number, since it uses as much as digits as its factorization.
12952084991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 50.
The spelling of 12952084991 in words is "twelve billion, nine hundred fifty-two million, eighty-four thousand, nine hundred ninety-one".
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