12953132110117 has 2 divisors, whose sum is σ = 12953132110118. Its totient is φ = 12953132110116.

The previous prime is 12953132110109. The next prime is 12953132110133. The reversal of 12953132110117 is 71101123135921.

It is a Cunningham number, because it is equal to 3599046²+1.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12953132110116 + 1 = 3599046^2 + 1^2 .

It is an emirp because it is prime and its reverse (71101123135921) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12953132110117 - 2³ = 12953132110109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12953132110817) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6476566055058 + 6476566055059.

It is an arithmetic number, because the mean of its divisors is an integer number (6476566055059).

Almost surely, 2^{12953132110117} is an apocalyptic number.

It is an amenable number.

12953132110117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12953132110117 is an equidigital number, since it uses as much as digits as its factorization.

12953132110117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11340, while the sum is 37.

The spelling of 12953132110117 in words is "twelve trillion, nine hundred fifty-three billion, one hundred thirty-two million, one hundred ten thousand, one hundred seventeen".