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1298114366651 is a prime number
BaseRepresentation
bin10010111000111101101…
…001010100110010111011
311121002122211012100112222
4102320331221110302323
5132232014234213101
62432202343554255
7162533325026144
oct22707551246273
94532584170488
101298114366651
11460588799a23
1218b6bba5b98b
1395547553b6b
1446b86d80acb
1523b7860401b
hex12e3da54cbb

1298114366651 has 2 divisors, whose sum is σ = 1298114366652. Its totient is φ = 1298114366650.

The previous prime is 1298114366621. The next prime is 1298114366657. The reversal of 1298114366651 is 1566634118921.

It is a strong prime.

It is an emirp because it is prime and its reverse (1566634118921) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1298114366651 - 222 = 1298110172347 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 1298114366593 and 1298114366602.

It is not a weakly prime, because it can be changed into another prime (1298114366657) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 649057183325 + 649057183326.

It is an arithmetic number, because the mean of its divisors is an integer number (649057183326).

Almost surely, 21298114366651 is an apocalyptic number.

1298114366651 is a deficient number, since it is larger than the sum of its proper divisors (1).

1298114366651 is an equidigital number, since it uses as much as digits as its factorization.

1298114366651 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1866240, while the sum is 53.

The spelling of 1298114366651 in words is "one trillion, two hundred ninety-eight billion, one hundred fourteen million, three hundred sixty-six thousand, six hundred fifty-one".