Base | Representation |
---|---|
bin | 11000001011101101… |
… | …00100111100001011 |
3 | 1020111210222120020021 |
4 | 30011312210330023 |
5 | 203042133020201 |
6 | 5544144441311 |
7 | 636506326033 |
oct | 140566447413 |
9 | 36453876207 |
10 | 12983095051 |
11 | 5562689523 |
12 | 2624019237 |
13 | 12bba33284 |
14 | 8b24088c3 |
15 | 50ec12ea1 |
hex | 305da4f0b |
12983095051 has 2 divisors, whose sum is σ = 12983095052. Its totient is φ = 12983095050.
The previous prime is 12983095043. The next prime is 12983095079. The reversal of 12983095051 is 15059038921.
It is a happy number.
12983095051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12983095051 - 23 = 12983095043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12983094989 and 12983095007.
It is not a weakly prime, because it can be changed into another prime (12983095001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6491547525 + 6491547526.
It is an arithmetic number, because the mean of its divisors is an integer number (6491547526).
Almost surely, 212983095051 is an apocalyptic number.
12983095051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12983095051 is an equidigital number, since it uses as much as digits as its factorization.
12983095051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 97200, while the sum is 43.
The spelling of 12983095051 in words is "twelve billion, nine hundred eighty-three million, ninety-five thousand, fifty-one".
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