Base | Representation |
---|---|
bin | 11000001100001001… |
… | …01110011010111111 |
3 | 1020112001221222211011 |
4 | 30012010232122333 |
5 | 203044110211103 |
6 | 5544400140051 |
7 | 636553004023 |
oct | 140604563277 |
9 | 36461858734 |
10 | 12986803903 |
11 | 5564791a97 |
12 | 2625307627 |
13 | 12bc731468 |
14 | 8b2ad2383 |
15 | 5101e6d6d |
hex | 30612e6bf |
12986803903 has 2 divisors, whose sum is σ = 12986803904. Its totient is φ = 12986803902.
The previous prime is 12986803889. The next prime is 12986803909. The reversal of 12986803903 is 30930868921.
It is a strong prime.
It is an emirp because it is prime and its reverse (30930868921) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12986803903 is a prime.
It is a super-2 number, since 2×129868039032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12986803909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6493401951 + 6493401952.
It is an arithmetic number, because the mean of its divisors is an integer number (6493401952).
Almost surely, 212986803903 is an apocalyptic number.
12986803903 is a deficient number, since it is larger than the sum of its proper divisors (1).
12986803903 is an equidigital number, since it uses as much as digits as its factorization.
12986803903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 49.
The spelling of 12986803903 in words is "twelve billion, nine hundred eighty-six million, eight hundred three thousand, nine hundred three".
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