Base | Representation |
---|---|
bin | 111100100010010011… |
… | …0101001010000000011 |
3 | 110102112220221020121221 |
4 | 1321010212221100003 |
5 | 4112220000000003 |
6 | 135415435055511 |
7 | 12251343524236 |
oct | 1710446512003 |
9 | 412486836557 |
10 | 130000000003 |
11 | 5015067a135 |
12 | 212408a1597 |
13 | c349ba4833 |
14 | 64134a941d |
15 | 35acd637bd |
hex | 1e449a9403 |
130000000003 has 2 divisors, whose sum is σ = 130000000004. Its totient is φ = 130000000002.
The previous prime is 129999999949. The next prime is 130000000007. The reversal of 130000000003 is 300000000031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130000000003 - 29 = 129999999491 is a prime.
It is not a weakly prime, because it can be changed into another prime (130000000007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000000001 + 65000000002.
It is an arithmetic number, because the mean of its divisors is an integer number (65000000002).
Almost surely, 2130000000003 is an apocalyptic number.
130000000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
130000000003 is an equidigital number, since it uses as much as digits as its factorization.
130000000003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9, while the sum is 7.
Adding to 130000000003 its reverse (300000000031), we get a palindrome (430000000034).
The spelling of 130000000003 in words is "one hundred thirty billion, three", and thus it is an aban number.
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