Base | Representation |
---|---|
bin | 10010111010101110000… |
… | …011010000000101111000 |
3 | 11121021112020202012002211 |
4 | 102322232003100011320 |
5 | 132244400023230240 |
6 | 2433113432104504 |
7 | 162631134321436 |
oct | 22725603200570 |
9 | 4537466665084 |
10 | 1300000211320 |
11 | 461366256a38 |
12 | 18bb47535134 |
13 | 9578816c695 |
14 | 46cc5601d56 |
15 | 23c38e67bea |
hex | 12eae0d0178 |
1300000211320 has 16 divisors (see below), whose sum is σ = 2925000475560. Its totient is φ = 520000084512.
The previous prime is 1300000211309. The next prime is 1300000211347. The reversal of 1300000211320 is 231120000031.
It is a super-2 number, since 2×13000002113202 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1300000211320.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16250002602 + ... + 16250002681.
Almost surely, 21300000211320 is an apocalyptic number.
1300000211320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1300000211320 is an abundant number, since it is smaller than the sum of its proper divisors (1625000264240).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300000211320 is a wasteful number, since it uses less digits than its factorization.
1300000211320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32500005294 (or 32500005290 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 1300000211320 its reverse (231120000031), we get a palindrome (1531120211351).
The spelling of 1300000211320 in words is "one trillion, three hundred billion, two hundred eleven thousand, three hundred twenty".
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