13000010321 has 2 divisors, whose sum is σ = 13000010322. Its totient is φ = 13000010320.

The previous prime is 13000010299. The next prime is 13000010323. The reversal of 13000010321 is 12301000031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10408080400 + 2591929921 = 102020^2 + 50911^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13000010321 is a prime.

It is a super-2 number, since 2×13000010321² (a number of 21 digits) contains 22 as substring.

Together with 13000010323, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13000010323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500005160 + 6500005161.

It is an arithmetic number, because the mean of its divisors is an integer number (6500005161).

Almost surely, 2^13000010321 is an apocalyptic number.

It is an amenable number.

13000010321 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000010321 is an equidigital number, since it uses as much as digits as its factorization.

13000010321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 13000010321 its reverse (12301000031), we get a palindrome (25301010352).

The spelling of 13000010321 in words is "thirteen billion, ten thousand, three hundred twenty-one".