Base | Representation |
---|---|
bin | 1011110100101100110100… |
… | …0110001111011100110000 |
3 | 1201000210022012002100110111 |
4 | 2331023031012033130300 |
5 | 3200443011033044440 |
6 | 43352042325511104 |
7 | 2511135262543042 |
oct | 275131506173460 |
9 | 51023265070414 |
10 | 13000012003120 |
11 | 416230195892a |
12 | 155b5a5872494 |
13 | 733b852cb95c |
14 | 32d2bd86ba92 |
15 | 1782607584ea |
hex | bd2cd18f730 |
13000012003120 has 160 divisors (see below), whose sum is σ = 31424570573760. Its totient is φ = 4997855969280.
The previous prime is 13000012003109. The next prime is 13000012003211. The reversal of 13000012003120 is 2130021000031.
It is a self number, because there is not a number n which added to its sum of digits gives 13000012003120.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1692485680 + ... + 1692493360.
It is an arithmetic number, because the mean of its divisors is an integer number (196403566086).
Almost surely, 213000012003120 is an apocalyptic number.
13000012003120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13000012003120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15712285286880).
13000012003120 is an abundant number, since it is smaller than the sum of its proper divisors (18424558570640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13000012003120 is an frugal number, since it uses more digits than its factorization.
13000012003120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7980 (or 7808 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 13000012003120 its reverse (2130021000031), we get a palindrome (15130033003151).
The spelling of 13000012003120 in words is "thirteen trillion, twelve million, three thousand, one hundred twenty".
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