Base | Representation |
---|---|
bin | 10010111010101110001… |
… | …010100000001001110000 |
3 | 11121021112101022202111112 |
4 | 102322232022200021300 |
5 | 132244401020041422 |
6 | 2433113540532452 |
7 | 162631156426214 |
oct | 22725612401160 |
9 | 4537471282445 |
10 | 1300002112112 |
11 | 461367335040 |
12 | 18bb480b1128 |
13 | 95788686902 |
14 | 46cc5978944 |
15 | 23c391e0ee2 |
hex | 12eae2a0270 |
1300002112112 has 80 divisors (see below), whose sum is σ = 2753961068544. Its totient is φ = 589572000000.
The previous prime is 1300002112111. The next prime is 1300002112163. The reversal of 1300002112112 is 2112112000031.
It is a super-2 number, since 2×13000021121122 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300002112111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 163497737 + ... + 163505687.
Almost surely, 21300002112112 is an apocalyptic number.
It is an amenable number.
1300002112112 is an abundant number, since it is smaller than the sum of its proper divisors (1453958956432).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300002112112 is a wasteful number, since it uses less digits than its factorization.
1300002112112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9958 (or 9952 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1300002112112 its reverse (2112112000031), we get a palindrome (3412114112143).
The spelling of 1300002112112 in words is "one trillion, three hundred billion, two million, one hundred twelve thousand, one hundred twelve".
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