Base | Representation |
---|---|
bin | 111100100010010011… |
… | …1110101000010101011 |
3 | 110102112221112000110201 |
4 | 1321010213311002223 |
5 | 4112220034413233 |
6 | 135415445453031 |
7 | 12251346256303 |
oct | 1710447650253 |
9 | 412487460421 |
10 | 130000310443 |
11 | 501508713a3 |
12 | 21240a11177 |
13 | c349c82c23 |
14 | 641354a603 |
15 | 35acdc577d |
hex | 1e449f50ab |
130000310443 has 2 divisors, whose sum is σ = 130000310444. Its totient is φ = 130000310442.
The previous prime is 130000310423. The next prime is 130000310459. The reversal of 130000310443 is 344013000031.
It is a strong prime.
It is an emirp because it is prime and its reverse (344013000031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130000310443 - 29 = 130000309931 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130000310443.
It is not a weakly prime, because it can be changed into another prime (130000310423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000155221 + 65000155222.
It is an arithmetic number, because the mean of its divisors is an integer number (65000155222).
Almost surely, 2130000310443 is an apocalyptic number.
130000310443 is a deficient number, since it is larger than the sum of its proper divisors (1).
130000310443 is an equidigital number, since it uses as much as digits as its factorization.
130000310443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 130000310443 its reverse (344013000031), we get a palindrome (474013310474).
The spelling of 130000310443 in words is "one hundred thirty billion, three hundred ten thousand, four hundred forty-three".
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