344013000031 has 2 divisors, whose sum is σ = 344013000032. Its totient is φ = 344013000030.

The previous prime is 344012999983. The next prime is 344013000109. The reversal of 344013000031 is 130000310443.

It is a weak prime.

It is an emirp because it is prime and its reverse (130000310443) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 344013000031 - 2¹⁹ = 344012475743 is a prime.

It is a super-2 number, since 2×344013000031² (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 344012999972 and 344013000008.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (344013000131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172006500015 + 172006500016.

It is an arithmetic number, because the mean of its divisors is an integer number (172006500016).

Almost surely, 2^344013000031 is an apocalyptic number.

344013000031 is a deficient number, since it is larger than the sum of its proper divisors (1).

344013000031 is an equidigital number, since it uses as much as digits as its factorization.

344013000031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 344013000031 its reverse (130000310443), we get a palindrome (474013310474).

The spelling of 344013000031 in words is "three hundred forty-four billion, thirteen million, thirty-one", and thus it is an aban number.