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130000322400 = 253521319321589
BaseRepresentation
bin111100100010010011…
…1110111111101100000
3110102112221112121212120
41321010213313331200
54112220040304100
6135415450024240
712251346336204
oct1710447677540
9412487477776
10130000322400
115015087a383
1221240a18080
13c349c884c0
146413550b04
1535acdc90a0
hex1e449f7f60

130000322400 has 288 divisors, whose sum is σ = 458083493280. Its totient is φ = 31832801280.

The previous prime is 130000322369. The next prime is 130000322407. The reversal of 130000322400 is 4223000031.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 130000322400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130000322407) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6010806 + ... + 6032394.

It is an arithmetic number, because the mean of its divisors is an integer number (1590567685).

Almost surely, 2130000322400 is an apocalyptic number.

130000322400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130000322400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (229041746640).

130000322400 is an abundant number, since it is smaller than the sum of its proper divisors (328083170880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130000322400 is a wasteful number, since it uses less digits than its factorization.

130000322400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21818 (or 21805 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 15.

Adding to 130000322400 its reverse (4223000031), we get a palindrome (134223322431).

The spelling of 130000322400 in words is "one hundred thirty billion, three hundred twenty-two thousand, four hundred".