Base | Representation |
---|---|
bin | 10010111010101110011… |
… | …101111010010011001011 |
3 | 11121021112201220020200212 |
4 | 102322232131322103023 |
5 | 132244403320344242 |
6 | 2433114241551335 |
7 | 162631250606441 |
oct | 22725635722313 |
9 | 4537481806625 |
10 | 1300007199947 |
11 | 46136a19a665 |
12 | 18bb4994554b |
13 | 95789748671 |
14 | 46cc6500b91 |
15 | 23c39898782 |
hex | 12eae77a4cb |
1300007199947 has 2 divisors, whose sum is σ = 1300007199948. Its totient is φ = 1300007199946.
The previous prime is 1300007199923. The next prime is 1300007200021. The reversal of 1300007199947 is 7499917000031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1300007199947 - 210 = 1300007198923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1300007199895 and 1300007199904.
It is not a weakly prime, because it can be changed into another prime (1300007189947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650003599973 + 650003599974.
It is an arithmetic number, because the mean of its divisors is an integer number (650003599974).
Almost surely, 21300007199947 is an apocalyptic number.
1300007199947 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300007199947 is an equidigital number, since it uses as much as digits as its factorization.
1300007199947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 428652, while the sum is 50.
The spelling of 1300007199947 in words is "one trillion, three hundred billion, seven million, one hundred ninety-nine thousand, nine hundred forty-seven".
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