130001011320281 has 2 divisors, whose sum is σ = 130001011320282. Its totient is φ = 130001011320280.

The previous prime is 130001011320263. The next prime is 130001011320331. The reversal of 130001011320281 is 182023110100031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121833470352400 + 8167540967881 = 11037820^2 + 2857891^2 .

It is a cyclic number.

It is not a de Polignac number, because 130001011320281 - 2¹⁴ = 130001011303897 is a prime.

It is a super-4 number, since 4×130001011320281⁴ (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (130001011320221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000505660140 + 65000505660141.

It is an arithmetic number, because the mean of its divisors is an integer number (65000505660141).

Almost surely, 2^{130001011320281} is an apocalyptic number.

It is an amenable number.

130001011320281 is a deficient number, since it is larger than the sum of its proper divisors (1).

130001011320281 is an equidigital number, since it uses as much as digits as its factorization.

130001011320281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 23.

The spelling of 130001011320281 in words is "one hundred thirty trillion, one billion, eleven million, three hundred twenty thousand, two hundred eighty-one".