130001011320331 has 2 divisors, whose sum is σ = 130001011320332. Its totient is φ = 130001011320330.

The previous prime is 130001011320281. The next prime is 130001011320359. The reversal of 130001011320331 is 133023110100031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130001011320331 - 2²¹ = 130001009223179 is a prime.

It is a super-2 number, since 2×130001011320331² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130001011320299 and 130001011320308.

It is not a weakly prime, because it can be changed into another prime (130001011320391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000505660165 + 65000505660166.

It is an arithmetic number, because the mean of its divisors is an integer number (65000505660166).

Almost surely, 2^{130001011320331} is an apocalyptic number.

130001011320331 is a deficient number, since it is larger than the sum of its proper divisors (1).

130001011320331 is an equidigital number, since it uses as much as digits as its factorization.

130001011320331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 130001011320331 its reverse (133023110100031), we get a palindrome (263024121420362).

The spelling of 130001011320331 in words is "one hundred thirty trillion, one billion, eleven million, three hundred twenty thousand, three hundred thirty-one".