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130001011320623 is a prime number
BaseRepresentation
bin11101100011110000111000…
…000110011010011100101111
3122001021222022222222200212012
4131203300320012122130233
5114014414032344224443
61140253350134031435
736245156151612212
oct3543607006323457
9561258288880765
10130001011320623
11384711348533a3
12126b70977a857b
135770072c57061
142416122615779
151006958264118
hex763c3819a72f

130001011320623 has 2 divisors, whose sum is σ = 130001011320624. Its totient is φ = 130001011320622.

The previous prime is 130001011320613. The next prime is 130001011320701. The reversal of 130001011320623 is 326023110100031.

It is a weak prime.

It is an emirp because it is prime and its reverse (326023110100031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130001011320623 - 244 = 112408825276207 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130001011320613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000505660311 + 65000505660312.

It is an arithmetic number, because the mean of its divisors is an integer number (65000505660312).

Almost surely, 2130001011320623 is an apocalyptic number.

130001011320623 is a deficient number, since it is larger than the sum of its proper divisors (1).

130001011320623 is an equidigital number, since it uses as much as digits as its factorization.

130001011320623 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 130001011320623 its reverse (326023110100031), we get a palindrome (456024121420654).

The spelling of 130001011320623 in words is "one hundred thirty trillion, one billion, eleven million, three hundred twenty thousand, six hundred twenty-three".