Base | Representation |
---|---|
bin | 11101100011110000111001… |
… | …010001111100110010110110 |
3 | 122001021222101101020201101022 |
4 | 131203300321101330302312 |
5 | 114014414102431401402 |
6 | 1140253352122301142 |
7 | 36245156512123400 |
oct | 3543607121746266 |
9 | 561258341221338 |
10 | 130001031122102 |
11 | 38471144a48558 |
12 | 126b70a23577b2 |
13 | 577007709acca |
14 | 24161250cbb70 |
15 | 1006959d762a2 |
hex | 763c3947ccb6 |
130001031122102 has 24 divisors (see below), whose sum is σ = 227612726895456. Its totient is φ = 55524574957488.
The previous prime is 130001031122099. The next prime is 130001031122153. The reversal of 130001031122102 is 201221130100031.
130001031122102 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2263693358 + ... + 2263750785.
It is an arithmetic number, because the mean of its divisors is an integer number (9483863620644).
Almost surely, 2130001031122102 is an apocalyptic number.
130001031122102 is a deficient number, since it is larger than the sum of its proper divisors (97611695773354).
130001031122102 is a wasteful number, since it uses less digits than its factorization.
130001031122102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4527444452 (or 4527444445 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 130001031122102 its reverse (201221130100031), we get a palindrome (331222161222133).
The spelling of 130001031122102 in words is "one hundred thirty trillion, one billion, thirty-one million, one hundred twenty-two thousand, one hundred two".
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