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130001100301 = 948231370987
BaseRepresentation
bin111100100010010101…
…0110101111000001101
3110102120000000010221201
41321010222311320031
54112220240202201
6135415514425501
712251356056142
oct1710452657015
9412500003851
10130001100301
1150151260876
1221241132291
13c34a19b5b7
1464136b43c9
1535acece801
hex1e44ab5e0d

130001100301 has 4 divisors (see below), whose sum is σ = 130002566112. Its totient is φ = 129999634492.

The previous prime is 130001100293. The next prime is 130001100347. The reversal of 130001100301 is 103001100031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130001100301 - 23 = 130001100293 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130001100391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 590671 + ... + 780316.

It is an arithmetic number, because the mean of its divisors is an integer number (32500641528).

Almost surely, 2130001100301 is an apocalyptic number.

It is an amenable number.

130001100301 is a deficient number, since it is larger than the sum of its proper divisors (1465811).

130001100301 is an equidigital number, since it uses as much as digits as its factorization.

130001100301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1465810.

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 130001100301 its reverse (103001100031), we get a palindrome (233002200332).

The spelling of 130001100301 in words is "one hundred thirty billion, one million, one hundred thousand, three hundred one".

Divisors: 1 94823 1370987 130001100301