Base | Representation |
---|---|
bin | 111100100010010101… |
… | …0110101111000111011 |
3 | 110102120000000011000102 |
4 | 1321010222311320323 |
5 | 4112220240202342 |
6 | 135415514430015 |
7 | 12251356056236 |
oct | 1710452657073 |
9 | 412500004012 |
10 | 130001100347 |
11 | 50151260908 |
12 | 2124113230b |
13 | c34a19b621 |
14 | 64136b441d |
15 | 35acece832 |
hex | 1e44ab5e3b |
130001100347 has 2 divisors, whose sum is σ = 130001100348. Its totient is φ = 130001100346.
The previous prime is 130001100293. The next prime is 130001100391. The reversal of 130001100347 is 743001100031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130001100347 - 214 = 130001083963 is a prime.
It is not a weakly prime, because it can be changed into another prime (130001100947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000550173 + 65000550174.
It is an arithmetic number, because the mean of its divisors is an integer number (65000550174).
Almost surely, 2130001100347 is an apocalyptic number.
130001100347 is a deficient number, since it is larger than the sum of its proper divisors (1).
130001100347 is an equidigital number, since it uses as much as digits as its factorization.
130001100347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 130001100347 its reverse (743001100031), we get a palindrome (873002200378).
The spelling of 130001100347 in words is "one hundred thirty billion, one million, one hundred thousand, three hundred forty-seven".
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