Base | Representation |
---|---|
bin | 11000001101101110… |
… | …11111110000111011 |
3 | 1020120000000011202111 |
4 | 30012313133300323 |
5 | 203111012110321 |
6 | 5545553313151 |
7 | 640104065461 |
oct | 140667376073 |
9 | 36500004674 |
10 | 13000113211 |
11 | 5571252518 |
12 | 26298657b7 |
13 | 12c24113a7 |
14 | 8b4798831 |
15 | 5114755e1 |
hex | 306ddfc3b |
13000113211 has 2 divisors, whose sum is σ = 13000113212. Its totient is φ = 13000113210.
The previous prime is 13000113209. The next prime is 13000113223. The reversal of 13000113211 is 11231100031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13000113211 - 21 = 13000113209 is a prime.
Together with 13000113209, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 13000113191 and 13000113200.
It is not a weakly prime, because it can be changed into another prime (13000113311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500056605 + 6500056606.
It is an arithmetic number, because the mean of its divisors is an integer number (6500056606).
Almost surely, 213000113211 is an apocalyptic number.
13000113211 is a deficient number, since it is larger than the sum of its proper divisors (1).
13000113211 is an equidigital number, since it uses as much as digits as its factorization.
13000113211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 13000113211 its reverse (11231100031), we get a palindrome (24231213242).
The spelling of 13000113211 in words is "thirteen billion, one hundred thirteen thousand, two hundred eleven".
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