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130001134431352 = 2323967992225121
BaseRepresentation
bin11101100011110000111111…
…011100000010110001111000
3122001021222122120122101000211
4131203300333130002301320
5114014414310403300402
61140253410252440504
736245162205210502
oct3543607734026170
9561258576571024
10130001134431352
113847119829a2a8
12126b7110a79134
1357700925ccb42
142416134b00d72
151006963e814d7
hex763c3f702c78

130001134431352 has 16 divisors (see below), whose sum is σ = 244772010439200. Its totient is φ = 64728598314240.

The previous prime is 130001134431269. The next prime is 130001134431353. The reversal of 130001134431352 is 253134431100031.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130001134431353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33996110649 + ... + 33996114472.

It is an arithmetic number, because the mean of its divisors is an integer number (15298250652450).

Almost surely, 2130001134431352 is an apocalyptic number.

It is an amenable number.

130001134431352 is a deficient number, since it is larger than the sum of its proper divisors (114770876007848).

130001134431352 is a wasteful number, since it uses less digits than its factorization.

130001134431352 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67992225366 (or 67992225362 counting only the distinct ones).

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 130001134431352 its reverse (253134431100031), we get a palindrome (383135565531383).

The spelling of 130001134431352 in words is "one hundred thirty trillion, one billion, one hundred thirty-four million, four hundred thirty-one thousand, three hundred fifty-two".

Divisors: 1 2 4 8 239 478 956 1912 67992225121 135984450242 271968900484 543937800968 16250141803919 32500283607838 65000567215676 130001134431352