Base | Representation |
---|---|
bin | 11101100011110000111111… |
… | …011100000010110000100101 |
3 | 122001021222122120122100220202 |
4 | 131203300333130002300211 |
5 | 114014414310403300034 |
6 | 1140253410252440245 |
7 | 36245162205210323 |
oct | 3543607734026045 |
9 | 561258576570822 |
10 | 130001134431269 |
11 | 3847119829a232 |
12 | 126b7110a79085 |
13 | 57700925ccaaa |
14 | 2416134b00d13 |
15 | 1006963e8147e |
hex | 763c3f702c25 |
130001134431269 has 2 divisors, whose sum is σ = 130001134431270. Its totient is φ = 130001134431268.
The previous prime is 130001134431149. The next prime is 130001134431353. The reversal of 130001134431269 is 962134431100031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 104390399334244 + 25610735097025 = 10217162^2 + 5060705^2 .
It is a cyclic number.
It is not a de Polignac number, because 130001134431269 - 232 = 129996839463973 is a prime.
It is a super-2 number, since 2×1300011344312692 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130001134401269) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000567215634 + 65000567215635.
It is an arithmetic number, because the mean of its divisors is an integer number (65000567215635).
Almost surely, 2130001134431269 is an apocalyptic number.
It is an amenable number.
130001134431269 is a deficient number, since it is larger than the sum of its proper divisors (1).
130001134431269 is an equidigital number, since it uses as much as digits as its factorization.
130001134431269 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 38.
The spelling of 130001134431269 in words is "one hundred thirty trillion, one billion, one hundred thirty-four million, four hundred thirty-one thousand, two hundred sixty-nine".
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