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130001134431269 is a prime number
BaseRepresentation
bin11101100011110000111111…
…011100000010110000100101
3122001021222122120122100220202
4131203300333130002300211
5114014414310403300034
61140253410252440245
736245162205210323
oct3543607734026045
9561258576570822
10130001134431269
113847119829a232
12126b7110a79085
1357700925ccaaa
142416134b00d13
151006963e8147e
hex763c3f702c25

130001134431269 has 2 divisors, whose sum is σ = 130001134431270. Its totient is φ = 130001134431268.

The previous prime is 130001134431149. The next prime is 130001134431353. The reversal of 130001134431269 is 962134431100031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104390399334244 + 25610735097025 = 10217162^2 + 5060705^2 .

It is a cyclic number.

It is not a de Polignac number, because 130001134431269 - 232 = 129996839463973 is a prime.

It is a super-2 number, since 2×1300011344312692 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130001134401269) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000567215634 + 65000567215635.

It is an arithmetic number, because the mean of its divisors is an integer number (65000567215635).

Almost surely, 2130001134431269 is an apocalyptic number.

It is an amenable number.

130001134431269 is a deficient number, since it is larger than the sum of its proper divisors (1).

130001134431269 is an equidigital number, since it uses as much as digits as its factorization.

130001134431269 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 38.

The spelling of 130001134431269 in words is "one hundred thirty trillion, one billion, one hundred thirty-four million, four hundred thirty-one thousand, two hundred sixty-nine".