130001213623 has 2 divisors, whose sum is σ = 130001213624. Its totient is φ = 130001213622.

The previous prime is 130001213593. The next prime is 130001213633. The reversal of 130001213623 is 326312100031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130001213623 is a prime.

It is a super-2 number, since 2×130001213623² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130001213594 and 130001213603.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130001213633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000606811 + 65000606812.

It is an arithmetic number, because the mean of its divisors is an integer number (65000606812).

Almost surely, 2^130001213623 is an apocalyptic number.

130001213623 is a deficient number, since it is larger than the sum of its proper divisors (1).

130001213623 is an equidigital number, since it uses as much as digits as its factorization.

130001213623 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 130001213623 its reverse (326312100031), we get a palindrome (456313313654).

The spelling of 130001213623 in words is "one hundred thirty billion, one million, two hundred thirteen thousand, six hundred twenty-three".